python独立log示例

Python math.log1p()方法 (Python math.log1p() method)

math.log1p() method is a library method of math module, it is used to get the natural logarithm of 1+x (base e), it accepts a number and returns the natural logarithm of 1+number on base e.

math.log1p()方法是数学模块的库方法，用于获取1 + x(以e为底)的自然对数，它接受一个数字并以e为基础返回1+数字的自然对数。

Note: If we provide anything else except a number, the method returns a TypeError – "TypeError: a float is required".

注意：如果我们提供除数字以外的任何其他内容，该方法将返回TypeError – “ TypeError：需要浮点数” 。

Syntax of math.log1p() method:

math.log1p()方法的语法：

math.log1p(x)

Parameter(s):x – is the number whose logarithm to be calculated.

参数： x –是要计算其对数的数字。

Return value: float – it returns a float value that is the natural logarithm of 1 + x.

返回值： float-返回一个浮点值，它是1 + x的自然对数。

Example:

例：

Input:    x = 21    # function call    print(math.log1p(x))    Output:    3.091042453358316

Python代码演示math.log1p()方法的示例 (Python code to demonstrate example of math.log1p() method)

# python code to demonstrate example of # math.log1p() method# importing math moduleimport math# log1p()x = 21print("Natural logarithm of 1 +", x, " is = ", math.log1p(x))x = 10.23print("Natural logarithm of 1 +", x, " is = ", math.log1p(x))

Output

输出量

Natural logarithm of 1 + 21  is =  3.091042453358316Natural logarithm of 1 + 10.23  is =  2.418588768750352

翻译自:

python独立log示例